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Re: Can anyone help me figure out this Geometry problem?
To be honest, I'm not sure what this question is supposed to be solving.
The only possible answer I can think of is the following: The only numbers that are equal for x/4 and y/5 are multiples of 4 equal x and multiples of 5 equal y (0 included.) What that has to do with the problem might need more explanation, perhaps I don't understand the context of the problem. BUT for x+1 = z/5 z = 5x+5 for all real numbers. x+1 = z/5 (multiply both sides by 5) 5x+5 = z Is there any more explanation on your assignment? |

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Re: Can anyone help me figure out this Geometry problem?
Quote:
Well, that's a bit different, then. However, I don't think that we have enough information to give an answer. The question can be restated as: X/4 + 1 = A/5 However, that's two unknowns and only one (usable) equation, so good luck finding a solution. Do you, perhaps, mean a question like this: (X + 4)/4 = (Y + A)/5 I don't believe that that is solvable either, though. (three unknowns, one equation.) So, were you given any more information? Edit: Also, how is this geometry? It seems to be just algebra.
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