[Math]: Negative fraction exponents

((x+3)^(-2/3))-((x+3)^(-1/3))=6

How the hell do I solve this crap? I graphed the equation on my calculator and calculated the intersection with y=6 and got -3.125, but I don't know how to do the algebra to arrive at this answer.

Negative exponents are the same as saying 1/(x^(positive exponent.))

So, if you have 2^-1 that would become 1/(2^1).

With 5^-2 it would become 1/(5^2) => 1/25

etc.

For fractional exponents, that's the same as saying bottom number root[x(top number)]

So, x^2/3 becomes the cubed root of (x squared).

4^5/6 = 6th root of (4^5) => 3.16

2^2/3 = cubed root of (2^2) => 1.58

Got the answer, thread can be closed if that's still what you do around here when questions get answered.