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Multiplying Rational Expressions
Okay, so I get a lot of these problems correct. This is the only problem I'm stuck on:
-2n ∙ 7n+7 _____ _____ 7(n+2) ∙ n+1 In case you're wondering since the forum messes it up, that problem is -2n over 7(n+2) multiplied by 7n+7 over n+1. Now, I'm looking at it right now and saying "Doesn't 7n+7 factor?" But would you factor it first? I've gotten it this far: -2n(7n+7) ___________ (7n+14)(n+1) I multiplied 7(n+2) from the original problem out and got the first bottom term if you're wondering. The answer in the back of the book says -2n over n+2, but I do not know how to get that answer. Can anyone help?
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Re: Multiplying Rational Expressions
You didn't really simplify the expression:
The original expression is: _-2n(7n + 7)__ 7(n + 2)(n + 1) 7n + 7 has a factor of 7 in it, so it can be expanded into 7(n + 1). Your expression is now: _-2n(7)(n + 1)_ 7(n + 2)(n + 1) Since 7 and n + 1 are in both the numerator and the denominator, they cancel, leaving: _-2n_ n + 2
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Re: Multiplying Rational Expressions
Awww, thank you! I get it now. I just did not know where to put the 7. Thanks again.
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Re: Multiplying Rational Expressions
I covered that in the eighth grade, but it's been a while since I've done it. (I'm in 9th)
Wow, so long. About a year, actually. Nice review, since I have Star tests coming.
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