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Old 12-22-2007, 09:54 AM
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Maths - Equation of the Line

Well, I had this question on my second year christmas exam. The answer I got was y - 6x = -8, but most other people I asked got along the lines of 6x - y = 16/-16.

Here's the question.

C (2, 4) and D (1, -2) are two points.
Given that the slope is 6,
and the formula is y - y1 = slope (x - x1)
What is the equation of the line?

If you could show the work aswell, that would be absolutely awe-inspiring.


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Old 12-22-2007, 10:03 AM
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Re: Maths - Equation of the Line

C and D are on this line, then?

So, from that we get that:

y=6x+b

Then sub in one of the points

4=6(2)+b
4=12+b
-8=b

y=6x-8 should be the equation of the line.
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Old 12-22-2007, 10:55 AM
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Re: Maths - Equation of the Line

GDw, that's skipping steps. The idea is for him to do it the hard way.

( y - 2 ) = 6( x - 4 )
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Old 12-22-2007, 12:32 PM
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Re: Maths - Equation of the Line

Quote:
Originally Posted by GDwarf
y=6x-8 should be the equation of the line.
Tasty! I don't suppose I'd lose marks for having it another way around?
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If, for some reason, you really, really, really want to contact me, I have an E-Mail address that I may still be using. The fun is in finding it.

EDIT: Ah! ZU's addictive! I'll be gone in a week, I swear.



His name is Awkin, he lives on the second floor. I'm not JAwkin! Everyone knows that it's Awkin! Ah? Eh? Know what I mean?
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