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Systems of Linear Equations
This question has to do with Systems of Linear Equations, the topic I'm studying in math. The qeustion sounds simple, but I'm stuck. In order to progress, I need to put:
3(x+2y) = 4(y-x) Into y=mx+b form. Can someone show me how I can rearrange this?
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#2
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Re: Systems of Linear Equations
Talk about easy......
Just kidding. What you do is apply the distributive property: multiplying 3 into (x+2y) to get 3x+6y. Do the same to the other side to get 4y-4x. 3x+6y=4y-4x Subtract the 3x from both sides and subtract the 4y from both sides, giving you: 2y=-7x Now divide both sides by 2: y=-7/2x is the correct form. Since b (the y-intercept) is zero, it doesn't have to be stated.
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