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Old 04-24-2006, 06:34 PM
Alexi Laiho is overrated.
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Systems of Linear Equations

This question has to do with Systems of Linear Equations, the topic I'm studying in math. The qeustion sounds simple, but I'm stuck. In order to progress, I need to put:

3(x+2y) = 4(y-x)

Into y=mx+b form. Can someone show me how I can rearrange this?
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Old 04-24-2006, 07:27 PM
Goron
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Re: Systems of Linear Equations

Talk about easy......

Just kidding.

What you do is apply the distributive property: multiplying 3 into (x+2y) to get 3x+6y. Do the same to the other side to get 4y-4x.

3x+6y=4y-4x

Subtract the 3x from both sides and subtract the 4y from both sides, giving you:

2y=-7x

Now divide both sides by 2:

y=-7/2x is the correct form. Since b (the y-intercept) is zero, it doesn't have to be stated.
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Old 04-24-2006, 07:30 PM
Alexi Laiho is overrated.
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Re: Systems of Linear Equations

Y'know, I really wish I could've remembered that from Grade 9.

Yes, it is easy, now that I see it.
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