Asymptotes

Have exam on wednesday i need to know if im right so any help would be great. Tell me how you got them to.

1. Identify any asymptotes, zeros, y-intercept, or holes

y= x^2-9/ x+2.

I know the vertical asymptote is -2 and there is no holes can anyone help me with the other ones plz!

No there are no holes, there are only holes if you have the same thing on the top as on the bottom, for example: (x-3)(x-5)/(x-3)

Then you would have a removable at 3.

As for the original equation, your x-intercepts(zeros) are -3 and 3.

(x^2-9) factors out to x-3 and x+3, then solve to get those intercepts.

The y-intercept is -4.5

Hope that helps

thanks man

awfully late... but there was also one inclined asymptote in y = x - 2....
you get it dividing x^2 - 9 by x + 2, the quotient (is this the word?) is the asymptote...