Fix'd. Thanks for telling me. :3

well worst case scenario, you can always get a lawn ticket for $20.

Ah, thank you
I'm seeing them in Toronto August 8th

"A freakin' 12-gauge, what do you think?"

Hello there, fellow Napoleon Dynamite lover.

Yeah, it's incredibly useful - and that was quite easy, in fact, shouldn't take more than a couple of minutes with a calculator.

A = pi *d^2 / 4



So we put it in this equation.



267 = pi * d^2 / 4
1068 = pi * d^2
3355,2 = d^2
sqrt 3355,2 = sqrt d^2


etc


well, the end result is basically that the rivets have a diameter of 19 mm.
I love construction sometimes.

(F = Force, N = Newton, 10 N = 1 kg)

Two steel plates with the same cross section, 60x12 mm, are joined by putting the edges over each other and riveted with three rivets in a row with the steel plate. The steel plates are being pulled with a force of F = 60 kN. Max allowed tension is 175 MPa.


Calculate the diameter of the rivets, if allowed shearing tension is 75 MPa.


Basically, since it's three rivets, they only take a third of the tension. This means the force on each rivet is 20 kN.



When shearing, things get more dangerous than normal tension, yet max allowed shearing tension is stated here. If it was just normal tension, we would have to multiply the allowed shearing tension by 0.6. This is not the case, however, and we may move on.


Max allowed shearing tension is 75 MPa, or something that's easier to understand, 75 N/mm^2. They are each being tensioned by 20 000 N. So basically 20 000 / 75 gives us an area of 266.667, or 267 mm^2.

But yeah, there's no problem in that, really. I could show you some examples of where I would use pi, if interested...

When I try to estimate how much a pillar can hold or how much I can shear an object without it breaking, pi is highly useful.

Wow :p I didn't think you would reply so soon. I will probably only have access to a computer if I go to a library, at least for the summr... I'll try to go some time soon, sometime next week. Hopefully you'll be on msn.